Let's pretend that each ticket costs 'p' dollars. Dea bought 6 tickets, so her total cost is 6p dollars. The tickets are on sale for 1.50 dollars off, so each ticket costs p - 1.50 dollars. If we put all this information together, Dea's total cost is 6 times (p - 1.50) dollars, which equals 51 dollars. To find the regular price of each ticket, we can solve the equation 6p - 9 = 51. After adding 9 to both sides, we get 6p = 60. Dividing both sides by 6, we find that p equals 10 dollars. So, each ticket's regular price is 10 dollars.

Question

Let's pretend that each ticket costs 'p' dollars. Dea bought 6 tickets, so her total cost is 6p dollars. The tickets are on sale for 1.50 dollars off, so each ticket costs p - 1.50 dollars. If we put all this information together, Dea's total cost is 6 times (p - 1.50) dollars, which equals 51 dollars. To find the regular price of each ticket, we can solve the equation 6p - 9 = 51. After adding 9 to both sides, we get 6p = 60. Dividing both sides by 6, we find that p equals 10 dollars. So, each ticket's regular price is 10 dollars.

In simpler words, each ticket usually costs 10 dollars. But since they were on sale for 1.50 dollars off, Dea paid 51 dollars for 6 tickets.

can you simplify this

Answer 1

Dea purchased 6 tickets at a regular price of $10 each. However, since the tickets were on sale for $1.50 off, she paid a total of $51 for all 6 tickets.