Saw the system of two linear equations -3x- 4y = -23 and 3x- 5y = 5. A. (5, -2) b. (-5, -2) c. (-5, 2) d. (5, 2)
We can solve the system of equations by using the method of elimination.
Given the equations:
-3x - 4y = -23 ----(1)
3x - 5y = 5 ----(2)
We can eliminate the x variable by adding equation (1) and equation (2):
-3x - 4y + 3x - 5y = -23 + 5
-9y = -18
Divide both sides of the equation by -9 to solve for y:
y = -18 / -9
y = 2
Now, substitute the value of y into either of the original equations. Let's use equation (1):
-3x - 4(2) = -23
-3x - 8 = -23
-3x = -23 + 8
-3x = -15
Divide both sides of the equation by -3 to solve for x:
x = -15 / -3
x = 5
Therefore, the solution to the system of equations is x = 5 and y = 2, or (5, 2).