If the reaction of an equation is CaO+HCl=CaCl2+H2O. What mass of calcium chloride is formed when 28.05g of calcium oxide reacts with excess hydrochloric acid? What mass of hydrochloric acid reacts with 28.05g of calcium oxide? What mass of water is produced?
To find the mass of calcium chloride formed, we need to use the balanced chemical equation and the molar masses of the substances involved.
1 mole of CaO reacts with 2 moles of HCl to produce 1 mole of CaCl2.
First, we calculate the moles of CaO:
Moles of CaO = Mass of CaO / Molar mass of CaO
Moles of CaO = 28.05g / 56.08g/mol
Moles of CaO = 0.5 mol
Since 1 mole of CaO reacts with 1 mole of CaCl2, the moles of CaCl2 formed will also be 0.5 mol.
Now, we can calculate the mass of CaCl2:
Mass of CaCl2 = Moles of CaCl2 * Molar mass of CaCl2
Mass of CaCl2 = 0.5 mol * (40.08g/mol + 2 * 35.45g/mol)
Mass of CaCl2 = 70.53g
Therefore, 70.53 grams of calcium chloride are formed when 28.05g of calcium oxide reacts with excess hydrochloric acid.
To find the mass of hydrochloric acid that reacts with 28.05g of calcium oxide, we need to use the stoichiometry of the balanced equation.
From the equation, we can see that 1 mole of CaO reacts with 2 moles of HCl. So, the moles of HCl reacting will be twice the moles of CaO.
Moles of HCl = 2 * Moles of CaO
Moles of HCl = 2 * 0.5 mol
Moles of HCl = 1 mol
Now, we can calculate the mass of HCl:
Mass of HCl = Moles of HCl * Molar mass of HCl
Mass of HCl = 1 mol * 36.46g/mol
Mass of HCl = 36.46g
Therefore, 36.46 grams of hydrochloric acid react with 28.05g of calcium oxide.
To find the mass of water produced, we also need to use the stoichiometry of the balanced equation.
From the equation, we can see that 1 mole of CaO reacts with 1 mole of H2O. So, the moles of water produced will be the same as the moles of CaO.
Moles of H2O = Moles of CaO = 0.5 mol
Now, we can calculate the mass of H2O:
Mass of H2O = Moles of H2O * Molar mass of H2O
Mass of H2O = 0.5 mol * 18.02g/mol
Mass of H2O = 9.01g
Therefore, 9.01 grams of water are produced when 28.05g of calcium oxide reacts with excess hydrochloric acid.