The Pyramid is an arena in Memphis, Tennessee. Its height is 321 ft., and its slant height is 436.5 ft. Find the length of the edge of the square base. Round the answer to the nearest tenth. (1 point) plz
To find the length of the edge of the square base, we can use the Pythagorean theorem.
Let's call the length of the edge of the square base "x".
We have the height of the pyramid as the vertical side, which is 321 ft.
We have the slant height as the hypotenuse, which is 436.5 ft.
Using the Pythagorean theorem, we have:
x^2 + 321^2 = 436.5^2
x^2 + 103041 = 190684.25
x^2 = 190684.25 - 103041
x^2 = 87643.25
x ≈ √87643.25 ≈ 296.0 (rounded to the nearest tenth)
Therefore, the length of the edge of the square base is approximately 296.0 ft.
nope
Sorry about that mistake. Let's try again.
To find the length of the edge of the square base, we can use the Pythagorean theorem.
Let's call the length of the edge of the square base "x".
We have the height of the pyramid as the vertical side, which is 321 ft.
We have the slant height as the hypotenuse, which is 436.5 ft.
Using the Pythagorean theorem, we have:
x^2 + 321^2 = 436.5^2
x^2 + 103041 = 190684.25
x^2 = 190684.25 - 103041
x^2 = 87643.25
x ≈ √87643.25 ≈ 296.0 (rounded to the nearest tenth)
Therefore, the length of the edge of the square base is approximately 296.0 ft.