Sphere A = 40 cubic inches
Sphere B = 10 cubic inches
How many inches more is the radius of sphere A than the radius of sphere B? Round your answer to the nearest tenths. (Use n = 3.14.)
The formula for the volume of a sphere is given by V = (4/3)πr^3, where V is the volume and r is the radius.
For sphere A, we have 40 = (4/3)(3.14)r_A^3.
Simplifying this equation, we get r_A^3 = 40 * (3/4) / 3.14 = 38.216.
Taking the cube root of both sides, we get r_A ≈ 3.498 inches.
For sphere B, we have 10 = (4/3)(3.14)r_B^3.
Simplifying this equation, we get r_B^3 = 10 * (3/4) / 3.14 = 9.554.
Taking the cube root of both sides, we get r_B ≈ 2.138 inches.
The difference in radius is approximately r_A - r_B = 3.498 - 2.138 ≈ 1.360 inches. Rounded to the nearest tenth, the answer is 1.4 inches. Answer: \boxed{1.4}.