the expenditure on roads,schools and water supply are in the ratio 7:15:2. if the expenditure on roads is D2800•00 find the expenditure on
1 school
2 what is the budget for these three projects
To find the expenditure on schools, we need to determine the ratio between the expenditure on roads and the expenditure on schools.
Since the ratio of expenditure on roads to schools is 7:15, we can set up the proportion:
7/15 = 2800/x
Cross multiplying and solving for x, we get:
7x = 15 * 2800
7x = 42,000
x = 42,000 / 7
x = 6000
Therefore, the expenditure on schools is D6000.
To find the budget for these three projects, we add up the expenditures on roads, schools, and water supply.
The ratio of expenditure on roads, schools, and water supply is 7:15:2, which is equivalent to 7x:15x:2x.
In this case, x is the common multiplier.
The budget is given by:
7x + 15x + 2x = 2800 + 6000 + y
24x = 8800 + y
y = 24x - 8800
Since the ratio of the expenditures is 7:15:2, we can substitute the values to find the budget:
y = 24 * 2800 - 8800
y = 67,200 - 8800
y = 58,400
Therefore, the budget for these three projects is D58400.