At a school play, one family bought 3 student tickets and 2 adult tickets for point $20.50. Another family bought 4 student tickets and 1 adult ticket for $19.00. What was the cost of one student ticket? $1.50 $2.50 $3.50 $3.90
Let's assume the cost of one student ticket is $x and the cost of one adult ticket is $y.
From the information given, we can form the following equations:
3x + 2y = 20.50 .....(1) (Family 1)
4x + y = 19.00 .....(2) (Family 2)
Multiplying equation (2) by 2, we get:
8x + 2y = 38.00 .....(3)
Now, subtracting equation (1) from equation (3), we get:
(8x + 2y) - (3x + 2y) = 38.00 - 20.50
Simplifying,
8x - 3x = 17.50
5x = 17.50
Dividing both sides by 5, we get:
x = 3.50
Therefore, the cost of one student ticket is $3.50.