find x and y of the systems of equations
2x-10y = -28
-10x+10y = -20
To solve this system of equations, we can add the two equations together to eliminate the y variable:
(2x-10y) + (-10x+10y) = -28 + (-20)
-8x = -48
To solve for x, divide both sides of the equation by -8:
x = (-48) / (-8) = 6
Now we can substitute this value of x into one of the original equations to find y. Let's use the first equation:
2x - 10y = -28
2(6) - 10y = -28
12 - 10y = -28
-10y = -28 - 12
-10y = -40
To solve for y, divide both sides of the equation by -10:
y = (-40) / (-10) = 4
Therefore, the solutions to the system of equations are x = 6 and y = 4.