use the rational exponent property to write and equivalent expression
\root(6)(n^(5))-2+1
\root(6)(n^(5))-2^((1)/(6))+1
(n^(5)-2)^((5)/(6))+1
(n^(5)-2)^((1)/(6))+1
(n^(6)-2)^((1)/(5))+1
Sorry, none of the equivalent expressions you provided is correct. Let me correct it for you:
Using the rational exponent property, we can write the expression \(\sqrt[6]{n^5}-2+1\) as \((n^5)^{\frac{1}{6}}-2^{\frac{1}{6}}+1\).