which equation has a graph perpendicular to the graph of 5x=20y-12?
To find the equation that has a graph perpendicular to the graph of 5x = 20y - 12, we need to rewrite the given equation in slope-intercept form (y = mx + b), where m is the slope of the line.
5x = 20y - 12
First, let's isolate y:
20y = 5x + 12
Next, divide both sides by 20 to solve for y:
y = (5/20)x + 12/20
Simplifying further:
y = (1/4)x + 3/5
The slope of the line is 1/4.
Perpendicular lines have slopes that are negative reciprocals of each other. Hence, the slope of the line perpendicular to 5x = 20y - 12 is -4.
Therefore, the equation with a graph perpendicular to 5x = 20y - 12 can be written as y = -4x + c, where c is a constant.