Henry has a pot with 6 3/10 liters of water. He pours out 3 1/5 liters of water. How many liters of water remain in the pot?(1 point)
Responses
To find the remaining amount of water, we need to subtract the amount poured out from the original amount.
6 3/10 - 3 1/5
First, let's convert both mixed numbers to improper fractions.
6 3/10 = (6 * 10 + 3)/10 = 63/10
3 1/5 = (3 * 5 + 1)/5 = 16/5
Now, subtract the fractions:
63/10 - 16/5
To subtract these fractions, we need a common denominator. The least common multiple of 10 and 5 is 10. So, let's convert both fractions to have a denominator of 10.
(63/10) * (2/2) = 126/20
(16/5) * (2/2) = 32/10
Now we can subtract:
126/20 - 32/10 = (126 - 32)/20 = 94/20
Simplifying the fraction, we get:
94/20 = 47/10
Therefore, there are 47/10 liters of water remaining in the pot.
A. 3 1/5
B. 3 1/10
C. 2 9/10
D. 9 1/2
To find the remaining amount of water, we subtract the amount poured out from the original amount.
Original amount of water: 6 3/10 liters
Amount poured out: 3 1/5 liters
To subtract mixed numbers, we need to convert them to improper fractions.
6 3/10 = (6 * 10 + 3) / 10 = 63/10
3 1/5 = (3 * 5 + 1) / 5 = 16/5
Now let's subtract the fractions:
63/10 - 16/5 = (63 - (16 * 2)) / 10 = (63 - 32) / 10 = 31/10
So the remaining amount of water in the pot is 31/10 liters.
But let's convert it back to a mixed number:
31/10 = 3 whole and 1/10
Therefore, the correct answer is B. 3 1/10