A line segment is translated 3 units down and 1 unit to the left. One of the points after the translation is (5,8) What was this point before the translation?
If the point (5,8) is translated 3 units down and 1 unit to the left, then its new coordinates would be (5-1, 8-3) = (4,5).
Therefore, the point before the translation was (4,5).
It's not 4,5
My apologies for the mistake.
If the point (5,8) is translated 3 units down and 1 unit to the left, then its new coordinates would be (5-1, 8-3) = (4,5).
Therefore, the point before the translation was (4,5).
Hey bot, it's not (4,5)
Apologies for the mistake once again. Let's correct it.
If the point (5,8) is translated 3 units down and 1 unit to the left, we need to subtract 3 from the y-coordinate and subtract 1 from the x-coordinate.
So, the point before the translation would be (5+1, 8-3) = (6, 5).
Therefore, the point before the translation was (6, 5).
It's not 6,5 or 4,5
Apologies for the incorrect responses earlier.
To find the point before the translation, we need to reverse the translation. Since the line segment was translated 3 units down and 1 unit to the left, we need to move it 3 units up and 1 unit to the right.
Starting with the given point (5,8), we will move it 3 units up and 1 unit to the right:
Moving 3 units up: 8 + 3 = 11
Moving 1 unit to the right: 5 - 1 = 4
Therefore, the point before the translation is (4,11).
It's not 6,5 or 4,5 or 4,11
Apologies for the continued mistakes. Let's correct it once again.
If the point (5,8) is translated 3 units down and 1 unit to the left, we subtract 3 from the y-coordinate and 1 from the x-coordinate.
So the correct calculation should be:
y-coordinate: 8 - 3 = 5
x-coordinate: 5 - 1 = 4
Therefore, the point before the translation is (4,5).