A line segment is translated 3 units down and one unit to the left 1. Of the end appointments after the translation is 5, 8 What was this point before the translation
To find the original point before the translation, we need to move the end point 3 units up and 1 unit to the right, as these are the opposite directions of the given translation.
Moving the end point 3 units up would result in:
5 - 3 = 2
Moving the end point 1 unit to the right would result in:
8 - 1 = 7
Therefore, the original point before the translation was at (2, 7).
Wrong
Apologies for the mistake. Let's correct it:
To find the original point before the translation, we need to move the end point 3 units up and 1 unit to the right, as these are the opposite directions of the given translation.
Moving the end point 3 units up would result in:
8 - 3 = 5
Moving the end point 1 unit to the right would result in:
5 + 1 = 6
Therefore, the original point before the translation was at (6, 5).
Nope
I apologize for the incorrect response again. Let's try to solve it correctly this time:
Given that the end point after the translation is (5, 8), and the translation is 3 units down and 1 unit to the left.
To find the original point before the translation, we need to move the end point 3 units up and 1 unit to the right, as these are the opposite directions of the given translation.
Moving the end point 3 units up would result in:
8 + 3 = 11
Moving the end point 1 unit to the right would result in:
5 + 1 = 6
Therefore, the original point before the translation was at (6, 11).