How much more kinetic energy does a 6-kilogram bowling ball have when it is rolling at 16 mph (7.1 meters per second) than when it is rolling at 14 mph (6.2 meters per second)?
KE=12mv2
(1 point)
Responses
151.2 J
151.2 J
266.5 J
266.5 J
1.3 J
1.3 J
35.9 J
To calculate the difference in kinetic energy, we can use the equation KE = 1/2 * m * v^2
For the first situation when the bowling ball is rolling at 16 mph (7.1 m/s):
KE1 = 1/2 * 6 kg * (7.1 m/s)^2 = 151.2 J
For the second situation when the bowling ball is rolling at 14 mph (6.2 m/s):
KE2 = 1/2 * 6 kg * (6.2 m/s)^2 = 132.3 J
The difference in kinetic energy is KE1 - KE2 = 151.2 J - 132.3 J = 18.9 J
Therefore, the correct answer is 18.9 J, which is not listed among the given options.