The sum of two numbers is 20. The difference between three times the first number and twice the second is 40. Solve for the two numbers.
*Remember to write the answers with a comma between but no spaces. big#,small#
Let's represent the two numbers as x and y.
From the first sentence, we can write the equation:
x + y = 20
From the second sentence, we can write the equation:
3x - 2y = 40
To solve this system of equations, we can use the method of substitution.
From the first equation, we can express y in terms of x:
y = 20 - x
Substituting this expression into the second equation, we have:
3x - 2(20 - x) = 40
3x - 40 + 2x = 40
5x - 40 = 40
5x = 80
x = 16
Substituting the value of x back into the first equation:
16 + y = 20
y = 20 - 16
y = 4
So, the two numbers are 16 and 4.