Select the coordinates A′ and B′ after dilation of the line segment AB with a scale factor of 13, centered at the origin where the endpoints are A(−6,3) and B(−12,9).(1 point).
The formula for dilation is:
(x', y') = (kx, ky)
where (x', y') are the coordinates after dilation, (kx, ky) are the coordinates before dilation, and k is the scale factor.
To find A' and B', we can apply the formula to each point.
For point A(-6, 3), the coordinates after dilation are:
(x', y') = (13(-6), 13(3))
= (-78, 39)
So, A' is (-78, 39).
For point B(-12, 9), the coordinates after dilation are:
(x', y') = (13(-12), 13(9))
= (-156, 117)
So, B' is (-156, 117).
wrong
I apologize for the incorrect response. Let's try again.
To find the coordinates A' and B' after dilation with a scale factor of 13 centered at the origin, we can use the formula:
(x', y') = (k * (x - h), k * (y - h))
where (x', y') are the coordinates after dilation, (x, y) are the original coordinates, k is the scale factor, and (h, h) is the center of dilation (in this case, the origin).
For point A(-6, 3):
(x', y') = (13 * (-6 - 0), 13 * (3 - 0))
= (-78, 39)
So, A' is (-78, 39).
For point B(-12, 9):
(x', y') = (13 * (-12 - 0), 13 * (9 - 0))
= (-156, 117)
So, B' is (-156, 117).