A big rig truck loses its breaks going down a steep highway. The truck has a mass of 36,200 kilograms and is traveling at 78 miles per hour (34.8 meters per second). How much kinetic energy does the truck have when the driver turns into the deep gravel of an emergency ramp?
KE=12mv2
(1 point)
Responses
21,919,824 J
110,120,400 J
629,880 J
43,839,648 J
To solve this problem, we need to use the formula for kinetic energy:
KE = 1/2 * m * v^2
where KE is the kinetic energy, m is the mass of the truck, and v is the velocity of the truck.
Substituting the given values into the formula, we get:
KE = 1/2 * 36,200 kg * (34.8 m/s)^2
Calculating this expression:
KE = 1/2 * 36,200 kg * 1210.2 m^2/s^2
KE ≈ 21,919,824 J
Therefore, the truck has approximately 21,919,824 Joules of kinetic energy when the driver turns into the deep gravel of the emergency ramp.