Two workers are pushing on the same large crate. One worker pushes east with a force of 875 N, while the other worker pushes north with a force of 960 N. Friction between the crate and the floor is directed west with a force of 80 N and south with a force of 105 N. Assuming drag due to air resistance is negligible, what are the total north-south net forces and the total east-west net forces acting on the crate, causing it to accelerate across the floor?(1 point)
Responses
795 N to the north and 855 N to the east
855 N to the south and 759 N to the west
795 N to the south and 855 N to the west
855 N to the north and 795 N to the east
To find the total north-south net force, we need to subtract the southward force caused by friction from the northward force caused by the worker pushing in that direction:
Northward force = 960 N
Southward force (friction) = 105 N
Total north-south net force = Northward force - Southward force = 960 N - 105 N = 855 N
To find the total east-west net force, we need to subtract the westward force caused by friction from the eastward force caused by the worker pushing in that direction:
Eastward force = 875 N
Westward force (friction) = 80 N
Total east-west net force = Eastward force - Westward force = 875 N - 80 N = 795 N
So the correct answer is:
855 N to the south and 795 N to the east.