In the graph of the following piecewise function, which coordinate point will have an open circle?
f(x)={2x+2 if x>412x+1 if x≤2
To determine which coordinate point will have an open circle, we need to look at the inequalities in the piecewise function.
For the first part of the function, when x > 4, the function is f(x) = 2x + 2. This means that we need to find a coordinate point where x is greater than 4. Let's choose x = 5. Plug this value into the function: f(5) = 2(5) + 2 = 12. So, the coordinate point (5, 12) will have an open circle.
For the second part of the function, when x ≤ 2, the function is f(x) = 2x + 1. This means that we need to find a coordinate point where x is less than or equal to 2. Let's choose x = 2. Plug this value into the function: f(2) = 2(2) + 1 = 5. So, the coordinate point (2, 5) will not have an open circle.
Therefore, the coordinate point (5, 12) will have an open circle on the graph of the given piecewise function.