A force of 2n stretches an elastic material by 16m what additional force will stretch the material 8m assuming the elastic limit does not exceeded
To find the additional force that will stretch the material 8m, we need to determine the relationship between force and stretch for this elastic material.
Assuming Hooke's Law applies (which states that the force required to stretch or compress a spring is directly proportional to the amount of stretch or compression):
F = k * x
Where:
F = force applied (in Newtons)
k = spring constant (in N/m)
x = stretch or compression length (in meters)
Given that a force of 2N stretches the material by 16m, we can substitute this into the equation:
2N = k * 16m
Simplifying the equation, we find:
k = 2N / 16m
k = 0.125 N/m
Now, we can calculate the additional force required to stretch the material by 8m:
F = k * x
F = 0.125 N/m * 8m
F = 1 N
Therefore, an additional force of 1N will stretch the material by 8m, assuming the elastic limit is not exceeded.