Let x be the number of adults originally going to the wedding. The number of children originally going is 95 - x. The cost of adults attending is 22x and the cost of children attending is 195 dollars. The total cost of food for the original attendees is 22x + 195, which equals 1955. Solving for x, we get x = 80. Thus, the number of children originally going is 95 - 80 = 15.
If Hal and Sal add 2 more adults and 2 more children, the total number of adults will be 82 and the total number of children will be 17.
The cost of the additional adults is 44 dollars and the cost of the additional children is 26 dollars.
The new total cost will be 22 * 82 + 13 * 17 + 44 + 26 = 1804.
Therefore, Hal and Sal will have to pay 151 dollars more if they add 2 adults and 2 children to their wedding bill.
make it sound like a 12 year old wrote it but keep it formal
Let's imagine there's this wedding, and we need to figure out how many adults and children are going. We'll use x for the number of adults and 95 - x for the number of children. The adults cost 22 dollars each, and the kids cost 195 dollars in total.
So, the total cost for food is 22x + 195, and we know that this comes out to be 1955 dollars. We can solve this equation to find x, which turns out to be 80. Yay!
That means there were originally 80 adults going to the wedding, and if we subtract that from 95, we find that there were 15 children.
Now, Hal and Sal want to add 2 more adults and 2 more children to the guest list. So the new total will be 82 adults and 17 children.
The extra adults will cost 44 dollars (2 adults * 22 dollars), and the extra children will cost 26 dollars (2 children * 13 dollars).
To find the new total cost, we add up the cost of the new adults and children, and with the old cost, it becomes 22 * 82 + 13 * 17 + 44 + 26 = 1804 dollars.
Now comes the fun part. If we compare this new cost with the old cost, we see that Hal and Sal have to pay 151 dollars more! Whoa! That's quite a bit, but hey, at least they're having a great wedding!