Let x be the number of adults originally going to attend the wedding.
The number of children originally going to attend the wedding is 95 - x.
The cost of the adults attending is 22x.
The cost of the children attending is 195 dollars.
The total cost of food for the original attendees is 22x + 195.
So, 22x + 195 = 1955.
Therefore, 22x = 1955 - 195 = 1760.
So, x = 1760 / 22 = 80.
The number of children originally going to attend the wedding is 95 - 80 = 15.
If Hal and Sal add 2 more adults and 2 more children, the total number of adults will be 80 + 2 = 82.
The total number of children will be 15 + 2 = 17.
The cost of the additional adults is 2 * 22 = 44 dollars.
The cost of the additional children is 2 * 13 = 26 dollars.
The new total cost will be 22 * 82 + 13 * 17 + 44 + 26 = 1804.
Therefore, Hal and Sal will have to pay 1804 - 1955 = 151 dollars more if they add 2 adults and 2 children to their wedding bill.
shorten this a lil
Let x be the number of adults originally going to the wedding. The number of children originally going is 95 - x. The cost of adults attending is 22x and the cost of children attending is 195 dollars. The total cost of food for the original attendees is 22x + 195, which equals 1955. Solving for x, we get x = 80. Thus, the number of children originally going is 95 - 80 = 15.
If Hal and Sal add 2 more adults and 2 more children, the total number of adults will be 82 and the total number of children will be 17.
The cost of the additional adults is 44 dollars and the cost of the additional children is 26 dollars.
The new total cost will be 22 * 82 + 13 * 17 + 44 + 26 = 1804.
Therefore, Hal and Sal will have to pay 151 dollars more if they add 2 adults and 2 children to their wedding bill.