f(x)=4x^2-50x+126
The given euation defines the function of f. for what value of x does f(x) reach its minimum?
To find the value of x at which f(x) reaches its minimum, we need to find the vertex of the parabola defined by the function f(x).
The vertex of a parabola with equation y = ax^2 + bx + c is given by the formula x = -b/(2a).
In this case, the equation is f(x) = 4x^2 - 50x + 126, so a = 4, b = -50, and c = 126.
Using the formula, we can calculate the value of x:
x = -(-50) / (2*4)
x = 50/8
x = 6.25
Therefore, the value of x at which f(x) reaches its minimum is 6.25.