Find the value of x.
An isosceles triangle is shown and the horizontal base at the bottom of the triangle extends out to the left of the triangle. The angle at the bottom right corner of the triangle and the exterior angle formed by the left side of the triangle and the horizontal line that extends at the bottom left of the image are labeled.An isosceles triangle is shown. The horizontal line at the bottom of the triangle extends out to the left of the triangle. The bottom right corner of the triangle is labeled left-parenthesis 3 x plus 8 right-parenthesis degrees. An exterior angle at the bottom left of the image is formed by the left side of the triangle and the horizontal base of the triangle that extends out past the triangle. This angle is labeled left-parenthesis 5 x plus 12 right-parenthesis degrees.
(1 point)
To find the value of x, we can set up an equation using the properties of angles in a triangle.
In an isosceles triangle, the base angles are congruent. Therefore, we can set up the equation:
(3x + 8) = (5x + 12)
Now, solve for x:
3x - 5x = 12 - 8
-2x = 4
x = -2
Therefore, the value of x is -2.