Determine the proportion of offspring in an FfEe x FfEe cross would have the genotype
ffee
To determine the proportion of offspring in an FfEe x FfEe cross that would have the genotype ffee, we need to understand the laws of Mendelian genetics.
In this case, we are dealing with a dihybrid cross, where two traits are being considered: the presence or absence of the dominant alleles F and E.
When two individuals heterozygous for two traits are crossed (FfEe x FfEe), the Punnett square for this cross would look like this:
F f
E FF Ff
e fF ff
From this Punnett square, we can see that there are four possible combinations of alleles for the offspring: FF, Ff, fF, and ff.
The genotype ffee can only occur if an offspring inherits the recessive alleles for both traits, which means that the genotype of the parents must be FfEe.
In this cross, the probability of an offspring inheriting the genotype ffee would be (1/4) x (1/4) = 1/16. This is because each allele combination has a 1/4 chance of occurring, and for the genotype ffee, both alleles must be recessive, hence the 1/4 x 1/4 = 1/16.
Therefore, the proportion of offspring in an FfEe x FfEe cross that would have the genotype ffee is 1/16.