Calculate the mass of ammonium nitrate that would contain 14g of nitrogen
The molar mass of ammonium nitrate (NH4NO3) can be calculated by summing the molar masses of its components:
Molar mass of nitrogen (N) = 14.01 g/mol
Molar mass of hydrogen (H) = 1.01 g/mol
Molar mass of oxygen (O) = 16.00 g/mol
Molar mass of ammonium nitrate (NH4NO3) = (1 * molar mass of nitrogen) + (4 * molar mass of hydrogen) + (3 * molar mass of oxygen)
= (1 * 14.01 g/mol) + (4 * 1.01 g/mol) + (3 * 16.00 g/mol)
= 28.04 g/mol + 4.04 g/mol + 48.00 g/mol
= 80.08 g/mol
To find the mass of ammonium nitrate containing 14 g of nitrogen, we can use the molar mass of ammonium nitrate calculated above:
Mass of ammonium nitrate = (Mass of nitrogen / Molar mass of nitrogen) * Molar mass of ammonium nitrate
= (14 g / 14.01 g/mol) * 80.08 g/mol
≈ 79.94 g
Therefore, the mass of ammonium nitrate that would contain 14 g of nitrogen is approximately 79.94 grams.