When 1.5g of a monovalent metal L were reacted with water and 600cm³ of gas was produced.Determine the relative atomic mass of L(Molar gas volume=24000cm³)
To determine the relative atomic mass of metal L, we need to first find the number of moles of metal L that reacted with water.
Given:
Mass of metal L = 1.5g
We can calculate the number of moles of metal L using the formula:
Number of moles = Mass / Molar mass
Since metal L is monovalent, its molar mass is equal to its relative atomic mass (RAM).
Number of moles of metal L = 1.5g / RAM
Next, we can calculate the volume of gas produced using the molar gas volume:
Volume of gas produced = 600cm³ / 24000cm³/mol = 0.025 mol
From the balanced chemical equation, we know that 1 mole of metal L reacts to produce 1 mole of gas. Therefore, the number of moles of metal L is equal to the volume of gas produced.
Number of moles of metal L = 0.025 mol
Setting these two expressions for the number of moles of metal L equal to each other, we can solve for the relative atomic mass (RAM):
1.5g / RAM = 0.025 mol
RAM = 1.5g / 0.025 mol = 60 g/mol
Therefore, the relative atomic mass of metal L is 60 g/mol.