Dg of potassium hydroxide were dissolved in distilled water to make 100cm³ of solution.50cm³ of the solution required 50cm³ of 2M nitric acid for complete neutralization.Calculate mass of D of potassium hydroxide
(KOH+HNO3~KNO3+H2O
From the given information, we can determine that the volume of 2M nitric acid required for complete neutralization is equal to the volume of potassium hydroxide solution:
50 cm³ KOH solution = 50 cm³ 2M HNO₃
To calculate the mass of KOH, we need to convert the volume of 2M nitric acid to moles, and then determine the moles of KOH. Finally, we can convert moles to mass using the molar mass of KOH.
First, calculate moles of nitric acid:
moles of HNO₃ = volume of HNO₃ (L) * concentration of HNO₃ (mol/L)
moles of HNO₃ = 0.050 L * 2 mol/L
moles of HNO₃ = 0.100 mol
Since the reaction is balanced (1:1 ratio between HNO₃ and KOH), the moles of KOH will also be 0.100 mol.
Now, calculate the molar mass of KOH:
molar mass of KOH (K = 39.10 g/mol, O = 16.00 g/mol, H = 1.01 g/mol)
molar mass of KOH = 39.10 g/mol + 16.00 g/mol + 1.01 g/mol
molar mass of KOH = 56.11 g/mol
Finally, calculate the mass of KOH:
mass of KOH = moles of KOH * molar mass of KOH
mass of KOH = 0.100 mol * 56.11 g/mol
mass of KOH = 5.61 g
Therefore, the mass of KOH (D) is 5.61 grams.