A big rig truck loses its breaks going down a steep highway. The truck has a mass of 36,200 kilograms and is traveling at 78 miles per hour (34.8 meters per second). How much kinetic energy does the truck have when the driver turns into the deep gravel of an emergency ramp?
KE=12mv2
(1 point)
Responses
43,839,648 J
43,839,648 J
110,120,400 J
110,120,400 J
629,880 J
629,880 J
21,919,824 J
To find the kinetic energy of the truck, we will use the formula:
KE = 0.5 * m * v^2
where KE is the kinetic energy, m is the mass of the truck, and v is the velocity.
Given that the mass of the truck is 36,200 kilograms and the velocity is 34.8 meters per second, we can substitute these values into the formula:
KE = 0.5 * 36,200 * (34.8)^2
Calculating this expression, we get:
KE = 0.5 * 36,200 * 1210.4
KE = 21,919,824 J
Therefore, the kinetic energy of the truck when the driver turns into the deep gravel of an emergency ramp is approximately 21,919,824 Joules.