a sciecne teacher has a supply of 50% sugar solution and a supply of 80% sugar solution. how much pf each solution shold the teacher mix together to get 105ml of 60% of sugar solution for an experiment
Let's assume the teacher needs to mix x milliliters of the 50% sugar solution and (105 - x) milliliters of the 80% sugar solution to obtain 105 ml of a 60% sugar solution.
To solve for x:
0.50x + 0.80(105 - x) = 0.60(105)
0.50x + 84 - 0.80x = 63
-0.30x = -21
x = -21 / -0.30
x ≈ 70
Therefore, the teacher should mix approximately 70 ml of the 50% sugar solution and (105 - 70) ml = 35 ml of the 80% sugar solution to obtain 105 ml of a 60% sugar solution.