Write the first five terms of the sequence in which the nth term is a_n=(n+1)!/n+1
To find the first five terms of the sequence, we need to plug in the values for n from 1 to 5 into the equation a_n = (n+1)! / (n+1).
For n = 1:
a_1 = (1+1)! / (1+1)
a_1 = 2! / 2
a_1 = 2 / 2
a_1 = 1
For n = 2:
a_2 = (2+1)! / (2+1)
a_2 = 3! / 3
a_2 = 6 / 3
a_2 = 2
For n = 3:
a_3 = (3+1)! / (3+1)
a_3 = 4! / 4
a_3 = 24 / 4
a_3 = 6
For n = 4:
a_4 = (4+1)! / (4+1)
a_4 = 5! / 5
a_4 = 120 / 5
a_4 = 24
For n = 5:
a_5 = (5+1)! / (5+1)
a_5 = 6! / 6
a_5 = 720 / 6
a_5 = 120
Therefore, the first five terms of the sequence are: 1, 2, 6, 24, 120.