Write the first five terms of the sequence defined by the explicit formula a_n=112(1/4)^n-1
When we plug in n = 1 into the formula, we get a_1 = 112(1/4)^(1-1) = 112(1/4)^0 = 112(1) = 112.
When we plug in n = 2 into the formula, we get a_2 = 112(1/4)^(2-1) = 112(1/4)^1 = 112(1/4) = 28.
When we plug in n = 3 into the formula, we get a_3 = 112(1/4)^(3-1) = 112(1/4)^2 = 112(1/16) = 7.
When we plug in n = 4 into the formula, we get a_4 = 112(1/4)^(4-1) = 112(1/4)^3 = 112(1/64) = 1.75.
When we plug in n = 5 into the formula, we get a_5 = 112(1/4)^(5-1) = 112(1/4)^4 = 112(1/256) = 0.4375.
Therefore, the first five terms of the sequence defined by the explicit formula a_n = 112(1/4)^(n-1) are 112, 28, 7, 1.75, and 0.4375.