What is the molarity of Sodium hydroxide solution containing 60 g NaOH in 500 cm³?
To find the molarity of a solution, we need to know the number of moles of solute (NaOH) and the volume of the solution (in liters).
First, let's calculate the number of moles of NaOH:
molar mass of NaOH (Na + O + H) = 22.99 g/mol + 16.00 g/mol + 1.01 g/mol = 40.00 g/mol
number of moles of NaOH = mass of NaOH / molar mass of NaOH
= 60 g / 40.00 g/mol
= 1.5 mol
Next, let's convert the volume of the solution from cm³ to liters:
volume of the solution = 500 cm³ * (1 L / 1000 cm³)
= 0.5 L
Now, we can calculate the molarity using the formula:
Molarity = moles of solute / volume of solution
Molarity = 1.5 mol / 0.5 L
= 3.0 M
Therefore, the molarity of the sodium hydroxide solution is 3.0 M.