Calculate the solute potential of a 0.20 M NaCl solution at 25° C. Remember from chemistry that NaCl breaks into two ions when it dissolves in water. Remember to convert all Celsius temperatures to Kelvin, simply by adding 273.
To calculate the solute potential of a 0.20 M NaCl solution at 25°C, we need to use the formula:
Ψs = -iCRT
Where:
Ψs = solute potential
i = ionization constant (for NaCl, i = 2 because it breaks into two ions)
C = molar concentration of the solution
R = ideal gas constant (0.0831 L·bar/mol·K)
T = temperature in Kelvin (25°C + 273 = 298 K)
Substituting the given values into the formula, we get:
Ψs = -2 x 0.20 x 0.0831 x 298
Now we can calculate the solute potential:
Ψs = -0.9889 bar
Therefore, the solute potential of a 0.20 M NaCl solution at 25°C is -0.9889 bar.