Calculate the solute potential of a 0.20 M NaCl solution at 25° C. Remember from chemistry that NaCl breaks into two ions when it dissolves in water
To calculate the solute potential of a 0.20 M NaCl solution at 25° C, we need to use the formula for solute potential:
Ψs = -iCRT
where:
Ψs is the solute potential,
i is the ionization constant (the number of particles the solute produces when it dissolves),
C is the molar concentration of the solute (in mol/L),
R is the gas constant (0.0831 L·atm/mol·K), and
T is the temperature in Kelvin.
Since NaCl dissociates into two ions (Na+ and Cl-) when it dissolves in water, the ionization constant (i) is 2.
The molar concentration (C) is given as 0.20 M.
The gas constant (R) is 0.0831 L·atm/mol·K.
To convert the temperature from Celsius to Kelvin, we add 273.15 to it. Thus, 25° C = 25 + 273.15 = 298.15 K.
Now, we can plug in the values into the formula:
Ψs = -(2)(0.20 M)(0.0831 L·atm/mol·K)(298.15 K)
Ψs = -(39.6504 L·atm/mol)
The solute potential of a 0.20 M NaCl solution at 25° C is approximately -39.6504 L·atm/mol.