What is the quantity of heat that will give out a bar of brass 380g is cooled from 97⁰c to 35⁰c? (Specific latent heat capacity of brass =380jkg-¹k-¹
The formula to calculate the quantity of heat (Q) is given by:
Q = mcΔT
Where:
Q = Quantity of heat
m = Mass of the object (in kg)
c = Specific heat capacity (in J/kg·K)
ΔT = Change in temperature (in K)
Given:
Mass of brass (m) = 380 g = 0.38 kg
Specific latent heat capacity of brass (c) = 380 J/kg·K
Initial temperature (T1) = 97 °C = 97 K
Final temperature (T2) = 35 °C = 35 K
ΔT = T2 - T1 = 35 K - 97 K = -62 K
Using the values in the formula:
Q = (0.38 kg)(380 J/kg·K)(-62 K)
Q = -88,088 J
Therefore, the quantity of heat that will be given out by the bar of brass when cooled from 97 °C to 35 °C is -88,088 J. Note that the negative sign indicates that heat is being released (given out) by the brass.