Henry and Samantha have $30 to spend on bags of feed at petting zoo. Each nag cost $3. Given that H and S
Henry and Samantha have $30 to spend on bags of feed at the petting zoo. Each bag costs $3. Let's denote the number of bags Henry buys as H and the number of bags Samantha buys as S. We are given that H + S = 10 (since there are 10 bags in total) and 3H + 3S = 30 (since each bag costs $3 and they have $30 total to spend).
From the first equation, we can solve for H in terms of S: H = 10 - S.
Substituting this value of H into the second equation, we get:
3(10 - S) + 3S = 30
30 - 3S + 3S = 30
30 = 30
This equation is true for any value of S. Therefore, there are infinite solutions to the problem. Each solution represents a different combination of bags that Henry and Samantha could purchase while still spending a total of $30.