y=3/2x^2 graph parabola. Plot five points on the parabola
To plot five points on the parabola given by y = (3/2)x^2, we can substitute different values of x into the equation and calculate the corresponding y-values.
Let's choose five x-values: -2, -1, 0, 1, and 2.
For x = -2:
y = (3/2)(-2)^2 = 3(4)/2 = 12/2 = 6
So, the first point is (-2, 6).
For x = -1:
y = (3/2)(-1)^2 = 3(1)/2 = 3/2
The second point is (-1, 3/2).
For x = 0:
y = (3/2)(0)^2 = 0
The third point is (0, 0).
For x = 1:
y = (3/2)(1)^2 = 3(1)/2 = 3/2
The fourth point is (1, 3/2).
For x = 2:
y = (3/2)(2)^2 = 3(4)/2 = 12/2 = 6
The fifth point is (2, 6).
Thus, the five points on the parabola y = (3/2)x^2 are (-2, 6), (-1, 3/2), (0, 0), (1, 3/2), and (2, 6).
Here is a graph showing the parabola and the plotted points:
Graph: https://www.desmos.com/calculator/i3ggprgtl5