If the Ka value is 1.1 x10^-4, The Kb for the conjugate base of PABA is
To find the value of Kb for the conjugate base of PABA (p-aminobenzoic acid), we can use the relationship between Ka and Kb for a weak acid and its conjugate base.
Ka * Kb = Kw
Since the Kw (ion product of water) is a constant at a specific temperature, we can use the value of Ka to calculate Kb.
Kw = 1.0 x 10^-14 (at 25°C)
Given Ka = 1.1 x 10^-4, we can rearrange the equation to solve for Kb:
Ka * Kb = Kw
Kb = Kw / Ka
Kb = (1.0 x 10^-14) / (1.1 x 10^-4)
Kb ≈ 9.09 x 10^-11