1. How many solutions does the system of equations have
3x=-12y+15 and x+4y=5
heyyy help pls
To determine the number of solutions, we can look at the slopes of the two equations.
The given system of equations can be written in slope-intercept form:
3x = -12y + 15 -> y = (-3/4)x + 5/4 -> Equation A
x + 4y = 5 -> 4y = -x + 5 -> y = (-1/4)x + 5/4 -> Equation B
The slopes of the two equations are -3/4 (Equation A) and -1/4 (Equation B).
Since the slopes are not equal, the lines representing the equations will intersect at a single point. Therefore, the system of equations has one unique solution.