Adult tickets to the fall play cost $6 and student tickets cost $3. The drama class sold 25 more student tickets than adult tickets to the fall play. If the class collected $660 from ticket sales, how many student tickets were sold?
Let A be the number of adult tickets and S be the number of student tickets.
From the problem, we know that A<S.
The cost of A adult tickets is 6A.
The cost of S student tickets is 3S.
The drama class sold 25 more student tickets than adult tickets to the fall play, so we know that S = A + 25.
The class collected $660 from ticket sales, so 6A + 3S = $660.
Substituting S = A + 25, we get 6A + 3(A + 25) = $660.
Combining like terms, we get 6A + 3A + 75 = $660.
Combining like terms again, we get 9A + 75 = $660.
Subtracting 75 from both sides, we get 9A = $585.
Dividing both sides by 9, we get A = $65.
Substituting this value back into the equation S = A + 25, we get S = $65 + $25 = $90.
Thus, the drama class sold 90 student tickets. Answer: \boxed{90}.