AC current is transmitted through a combination of two step-down transformers.The original potential difference is 1200 v,there is originally a current of 30A,and the primary and secondary coils in the first transformer have 1000 coils and 600 coils.If the 2nd transformer has a potential difference of 100 v in it's secondary coil,what is the current in its secondary coil?
To solve this problem, we can use the transformer equation:
V1 / V2 = N1 / N2 (eq. 1)
where V1 is the potential difference in the primary coil, V2 is the potential difference in the secondary coil, N1 is the number of coils in the primary coil, and N2 is the number of coils in the secondary coil.
According to the problem, V1 = 1200 V, N1 = 1000 coils, and N2 = 600 coils.
Plugging these values into eq. 1, we get:
1200 V / V2 = 1000 coils / 600 coils
Cross-multiplying:
1200 V * 600 coils = 1000 coils * V2
720000 V*coils = 1000 coils * V2
Dividing both sides by 1000 coils:
720 V = V2
So, the potential difference in the secondary coil is 720 V.
Now, we can use Ohm's law to find the current in the secondary coil. Ohm's law states:
I = V / R (eq. 2)
where I is the current, V is the potential difference, and R is the resistance.
According to the problem, V2 = 100 V. We don't know the resistance, but since we are dealing with a transformer, we assume that the resistance in the primary and secondary coils is negligible. Therefore, we can ignore the resistance in our calculations.
Plugging these values into eq. 2, we get:
I = 100 V / R
Since R is negligible, the current I in the secondary coil is 100 A.
Therefore, the current in the secondary coil of the second transformer is 100 A.