How much water has been heated if it took 20000J to heat it by 80C? (Specific Heat Capacity of water is 4200 J/kgC)
To determine the amount of water that has been heated, we can use the equation:
Q = mcΔT
Where:
Q is the heat absorbed by the water (in joules),
m is the mass of the water (in kilograms),
c is the specific heat capacity of water (in joules per kilogram degree Celsius), and
ΔT is the change in temperature of the water (in degree Celsius).
We are given:
Q = 20000 J
ΔT = 80 °C
c = 4200 J/kg°C
Rearranging the equation, we can solve for the mass (m):
m = Q / (c * ΔT)
Substituting the given values:
m = 20000 J / (4200 J/kg°C * 80 °C)
m = 20000 J / (336000 J/kg)
m ≈ 0.0595 kg
Therefore, approximately 0.0595 kg (or 59.5 grams) of water has been heated.