A car with a mass of 1300kg travels at 3.24 m/s and bumps into a stopped car with a mass of 1350 kg. After the collision, the two cars stick together and move forward. How fast will they both move forward? Round your answer to two decimal places. (1 point) Responses 1.10 m/s 1.10 m/s 1.62 m/s 1.62 m/s 3.36 m/s 3.36 m/s 1.59 m/s
To solve this problem, we can use the principle of conservation of momentum.
The momentum of an object is given by the formula: momentum = mass * velocity.
Before the collision, the momentum of the first car is 1300 kg * 3.24 m/s = 4212 kg m/s.
The momentum of the second car is 1350 kg * 0 m/s = 0 kg m/s because it is stopped.
After the collision, the two cars stick together and move forward as one unit. Let's call their final velocity v.
The total mass of the two cars is 1300 kg + 1350 kg = 2650 kg.
Using the conservation of momentum, we can say:
4212 kg m/s + 0 kg m/s = 2650 kg * v
4212 kg m/s = 2650 kg * v
Dividing both sides by 2650 kg:
v = 4212 kg m/s / 2650 kg
v ≈ 1.59 m/s
Therefore, the two cars will move forward at a speed of approximately 1.59 m/s.