Use the table to answer the question.
x Substituted Evaluate True Statement?
−23
−
23
0
12
For the quadratic equation x2+20x=69
x
2
+
20
x
=
69
, complete the table by testing each of the given values to determine whether it is a solution. Identify which one of these values is in the solution set.
(1 point)
Only x=
x
=
$$26incorrect is in the solution set.
To evaluate whether a given value is a solution for the quadratic equation x^2 + 20x = 69, substitute the value into the equation and check if the equation is true.
Using the given values from the table:
For x = -23:
Substituting -23 into x^2 + 20x = 69:
(-23)^2 + 20(-23) = 529 - 460 = 69, which is true. (Yes, -23 is a solution)
For x = 23:
Substituting 23 into x^2 + 20x = 69:
(23)^2 + 20(23) = 529 + 460 = 989, which is not equal to 69. (No, 23 is not a solution)
For x = 0:
Substituting 0 into x^2 + 20x = 69:
(0)^2 + 20(0) = 0 + 0 = 0, which is not equal to 69. (No, 0 is not a solution)
For x = 12:
Substituting 12 into x^2 + 20x = 69:
(12)^2 + 20(12) = 144 + 240 = 384, which is not equal to 69. (No, 12 is not a solution)
The only value from the given table that is a solution to the equation x^2 + 20x = 69 is x = -23.