Indigo has some nickels and some dimes. She has no less than 15 coins worth at most $1 combined. If Indigo has 9 dimes, determine the maximum number of nickels that she could have.
The 9 dimes are worth 9*10=<<9*10=90>>90 cents
If the amount of money from the nickels when represented in cents is n, the total amount of money represented in cents is 90+n
The minimum number of nickels is gotten when the total amount is at most $1 which is 100 cents.
90+n<=100
Subtracting 90 from each side of the inequality gives n<=10
Therefore the minimum number of nickels is 10 if Indigo has 9 dimes.
Anything above 10 nickels will make the total over $1, meaning the maximum number of nickels that she could have is <<10=10>>10. Answer: \boxed{10}.
wrong
Apologies for the mistake. Let's correct it:
Since each nickel is worth 5 cents and each dime is worth 10 cents, the total value of the dimes is 9 * 10 = 90 cents.
Let n be the maximum number of nickels.
Each nickel adds 5 cents to the total value, so the maximum total value is 90 + 5n.
We know that the total value must be at most 100 cents (or $1), so we have the inequality:
90 + 5n ≤ 100
Subtract 90 from both sides to isolate 5n:
5n ≤ 10
Divide both sides by 5 to solve for n:
n ≤ 2
Therefore, the maximum number of nickels Indigo could have is 2.