AC current is transmitted through a combination of two step-down transformers. the original potential difference is 1200V, there is originally a current of 30A, and the primary and secondary coils in the first transformer have 1000 coils and 600 coils respectively. if the second transformer has a potential difference of 100V in its secondary coil, what is the current in its secondary coil?
To solve this problem, we can apply the transformer equation:
V1/V2 = N1/N2
Where V1 and V2 are the potential differences in the primary and secondary coils of the transformer, and N1 and N2 are the number of coils in the primary and secondary coils, respectively.
For the first transformer:
V1 = 1200V
N1 = 1000
N2 = 600
Using the transformer equation:
1200/ V2 = 1000/ 600
Cross-multiplying:
1200 * 600 = 1000 * V2
V2 = (1200 * 600) / 1000
V2 = 720V
Now that we have the potential difference in the secondary coil of the first transformer, we can use this value along with the potential difference in the secondary coil of the second transformer to find the current in the secondary coil of the second transformer.
V2 = 720V
V2' = 100V
We can again apply the transformer equation:
V2/ V2' = N2/ N2'
Where N2 is the number of coils in the secondary coil of the second transformer, and N2' is the number of coils in the output coil, which we need to find.
Using the transformer equation:
720 / 100 = N2 / N2'
Cross-multiplying:
720 * N2' = 100 * N2
N2' = (100 * N2) / 720
N2' = (100 * N2) / 720
However, the values of N2 and N2' are not provided, so it is not possible to determine the current in the secondary coil of the second transformer without this information.