Ocean water is a mixture of water and salt. Suppose you let 100 grams of ocean water sit out in the Sun. Eventually, you notice all the water has vanished and only 3.5 grams of solid salt remains. How much water must have been in the solution? (1 point)
• 96.5 grams
• 95 grams
• 103.5 grams
• 100 grams
To find the amount of water that must have been in the solution, we can subtract the mass of the solid salt from the initial mass of the ocean water.
Initial mass of the ocean water = 100 grams
Mass of solid salt remaining = 3.5 grams
Mass of water = Initial mass of the ocean water - Mass of solid salt remaining
Mass of water = 100 grams - 3.5 grams = 96.5 grams
Therefore, the amount of water that must have been in the solution is 96.5 grams.
So, the correct answer is:
• 96.5 grams