Tickets to the high school reunion cost $35 with a meal and $25 without a meal. The reunion committee sells 70 tickets for $2,250.
How many tickets of the type without a meal were sold?
Let x be the number of tickets sold with a meal.
Thus 70 - x is the number of tickets sold without a meal.
Tickets with a meal go for 35 * x dollars, and tickets without a meal go for 25 * (70 - x) dollars.
So, the total revenue from tickets is 35x + 25(70 - x).
The total revenue from tickets sold is $2250.
Therefore, 35x + 25(70 - x) = 2250.
Thus, 35x + 1750 - 25x = 2250.
Therefore, 10x = 500.
Thus, x = <<50=50>>50.
Therefore, 70 - x = 70 - 50 = <<70-50=20>>20.
So, 20 tickets without a meal were sold. Answer: \boxed{20}.