How much more kinetic energy does a 6 kg bowling ball have when it’s rolling at 16 mph 7.1 m/s then when it is rolling at 14 mph 6.2 m/s
To calculate the kinetic energy, we can use the formula: K.E. = (1/2) * m * v^2, where m is the mass of the object and v is its velocity.
First, let's calculate the kinetic energy of the bowling ball when it's rolling at 16 mph (7.1 m/s):
K.E. = (1/2) * 6 kg * (7.1 m/s)^2
K.E. = (1/2) * 6 kg * 50.41 m^2/s^2
K.E. = 150.24 J (rounded to two decimal places)
Next, let's calculate the kinetic energy of the bowling ball when it's rolling at 14 mph (6.2 m/s):
K.E. = (1/2) * 6 kg * (6.2 m/s)^2
K.E. = (1/2) * 6 kg * 38.44 m^2/s^2
K.E. = 115.32 J (rounded to two decimal places)
The difference in kinetic energy between the two situations is:
Kinetic energy at 16 mph - Kinetic energy at 14 mph = 150.24 J - 115.32 J = 34.92 J (rounded to two decimal places)
Therefore, the bowling ball has approximately 34.92 J more kinetic energy when rolling at 16 mph compared to when it's rolling at 14 mph.